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PHP ftell() | Find Current Position of File Pointer
The PHP ftell() function is used when we need to find the current position of file pointer in the file. For example:
<?php $file = "fresherearth.txt"; $fp = fopen($file, "r"); $character = fgetc($fp); echo $character; $currentPos = ftell($fp); echo "<br>The current position of file pointer: " . $currentPos; fclose($fp); ?>
The output produced by above PHP example on ftell() function is:
And here is the snapshot of the file fresherearth.txt used in above example:
Let me modify the above example, to convert to a self-defined example on ftell() function in PHP:
<?php $fp = fopen("fresherearth.txt", "r"); if($fp) { echo "<p>The current position: " .ftell($fp). "</p>"; echo "<p>The first character: " .fgetc($fp). "</p>"; echo "<p>Now the current position: " .ftell($fp). "</p><hr>"; echo "<p>The next (second) character: " .fgetc($fp). "</p>"; echo "<p>The current position: " .ftell($fp). "</p><hr>"; echo "<p>The next (third) character: " .fgetc($fp). "</p>"; echo "<p>The current position: " .ftell($fp). "</p>"; fclose($fp); } else echo "<p>Unable to open the file</p>"; ?>
Now the output should be:
PHP ftell() Syntax
The syntax of ftell() function in PHP, is:
ftell(filePointer)
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