C Program to Find the Total Number of Digits in a Given Number

In this article, we will learn to create a program in C that will ask the user to enter any number (at run-time) to find and print the total number of digits present in that given number. Here is the program:

#include<stdio.h>
#include<conio.h>
int main()
{
    int num, tim=0;
    printf("Enter any number: ");
    scanf("%d", &num);
    while(num>0)
    {
        tim++;
        num = num/10;
    }
    printf("\nTotal number of Digit = %d", tim);
    getch();
    return 0;
}

As the above program was written in the Code::Blocks IDE, here is the output you will also get on your output screen after a successful build and run. This is the first snapshot of the sample run:

Supply any number, say 24304, and press ENTER to see the output. As the number 24304 has a total of 5 digits, here is the output you will get:

Here are some of the main steps used in the above program:

• Receive any number as input.
• Create a while loop that runs until the number holds a value that is greater than 0.
• Inside the while loop, increment a variable, say tim, that is responsible for counting the total number of digits present inside the given number.
• Never forget to initialize the variable tim with 0 at the start of the program inside the main() function.
• After incrementing the value of the variable tim inside the while loop, divide the given number by 10 for the next check and increment.
• In this way, after exiting from the while loop, the variable tim holds the value that will be the value of the total number of digits present in the given number.

C Quiz